Answer :
The voltage drop across each lamp in this series circuit is 2 V. In a series circuit, the voltage is divided among the components. Since there are three identical lamps and a 6 V battery, the total voltage drop across all three lamps must be 6 V.
To find the voltage drop across each lamp, we can divide the total voltage by the number of lamps:
Step 1: Determine the total voltage supplied by the battery, which is 6 V in this case.
Step 2: Count the number of identical lamps connected in series, which is 3.
Step 3: Divide the total voltage by the number of identical lamps: 6 V ÷ 3 = 2 V.
Therefore, the voltage drop across each lamp is 2 V. It's important to note that in a series circuit, the current remains the same throughout the circuit, but the voltage drops as it passes through each component.
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