High School

This time we have a crate of mass 37.9 kg on an inclined surface, with a coefficient of kinetic friction of 0.167. Instead of pushing on the crate, you let it slide down due to gravity. What must the angle of the incline be in order for the crate to slide with an acceleration of 5.93 m/s²?

A. 64.5 degrees
B. 34.6 degrees
C. 46.1 degrees
D. 23.1 degrees

Answer :

The angle of the incline must be approximately 18.8 degrees for the crate to slide with an acceleration of 5.93 m/s^2.

When the crate slides down the inclined surface, there are two main forces acting on it: the gravitational force (mg) and the frictional force (μmg) due to kinetic friction. The component of the gravitational force parallel to the incline is mgsinθ, where θ is the angle of the incline. The equation of motion for the crate along the incline can be written as:

mgsinθ - μmg = ma,

where m is the mass of the crate, g is the acceleration due to gravity, μ is the coefficient of kinetic friction, and a is the acceleration of the crate.

Rearranging the equation, we get:

gsinθ - μg = a.

Substituting the given values, g = 9.8[tex]m/s^2[/tex], μ = 0.167, and a = 5.93 [tex]m/s^2[/tex], we can solve for θ:

9.8sinθ - 0.167 * 9.8 = 5.93.

Simplifying the equation and solving for θ, we find:

θ ≈ 18.8 degrees.

Therefore, the angle of the incline must be approximately 18.8 degrees for the crate to slide with an acceleration of 5.93 m/s^2.

Learn more about gravity here :

https://brainly.com/question/31321801

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