Answer :
This goes up and down. PO = 40cm, OQ 73cm, and the mass at A is 60 kg. Then the mass at B is 3.35 kg.
To find the mass at B, we can use the principle of moments. The principle of moments states that "the sum of the clockwise moments about any point equals the sum of the anticlockwise moments about the same point.
"Here, we have a system of two weights, A and B, which are suspended from a pulley and are attached to opposite ends of a light, inextensible rope passing over the pulley. We can consider the midpoint of the rope as the pivot point for the principle of moments.
Now, let's apply the principle of moments:
Clockwise moments = (60 × 0.4) Nm (as the distance of A from the pivot point is 0.4m)
Anticlockwise moments = F × 0.73 Nm (as the distance of B from the pivot point is 0.73m)where F is the weight of B in Newtons.
So, according to the principle of moments,60 × 0.4 = F × 0.73⇒ F = (60 × 0.4) ÷ 0.73⇒ F ≈ 32.88 N
So, the weight of B is approximately 32.88 N.
Now, we can use the formula, weight = mass × acceleration due to gravity (g)where acceleration due to gravity, g = 9.81 m/s²
weight of B = 32.88 N⇒ mass of B × 9.81 = 32.88⇒ mass of B = 3.35 kg
Therefore, the mass at B is approximately 3.35 kg.
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