Answer :
The resulting pressure is 378.04 Pa and the pressure in the small tube is approximately 413686.4 Pa.
The resulting pressure can be calculated using the formula
P = ρgh,
where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the height drop.
Assuming the fluid is water, the density of water is approximately 1000 kg/m³
Convert the height drop from mm to meters.
height drop = 38.2 mm / 1000 = 0.0382 m
Using the formula P = ρgh:
P = (1000 kg/m³) * (9.8 m/s²) * (0.0382 m)
P = 378.04 Pa
Therefore, the resulting pressure is 378.04 Pa.
- We need to use Bernoulli's equation, which states that the total pressure in a fluid system is constant. The total pressure includes the static pressure (pressure exerted by the fluid), dynamic pressure (pressure due to the fluid's velocity), and gravitational potential energy pressure (pressure due to the fluid's height).
Since both the large and small tubes have the same diameter, the velocity of water at both points will be the same.
Therefore, the dynamic pressure will be equal at the inlet and the small tube.
So, the pressure at the small tube will be equal to the pressure at the inlet (60 psi) plus the resulting pressure (375.56 Pa) from the height drop.
Since 1 psi is approximately equal to 6894.76 Pa, we can convert 60 psi to Pa:
60 psi × 6894.76 Pa/psi = 413686.4 Pa
Therefore, the pressure in the small tube is approximately 413686.4 Pa.
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