The width of a rectangle is 2 meters less than the length. If the area of the rectangle is 120 square meters, find the length and width of the rectangle.

Given a rectangle's area of 120 square meters and that its width is 2 meters less than its length, solving the parameters results in a length of 12 meters and a width of 10 meters.

Explanation:

Given that for a rectangle, the area (Area) is the product of the length (L) and the width (W), and it's mentioned that the width is 2 meters less than the length of the rectangle, i.e., W = L - 2. We also know that the area (A) is 120 square meters.

Equating A = LW to the known values, we get 120 = L(L - 2).

This leads to a quadratic equation L² - 2L - 120 = 0. Solving this quadratic equation for positive L (since length cannot be negative), we get L = 12 meters. Then, using the width equation, we get W = L - 2 = 10 meters.

So, the rectangle's length is 12 meters and the width is 10 meters.

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