The weight of an object on Earth is 196 N. What will be its weight on the surface of the moon if the acceleration due to gravity on the moon is one-sixth of that on Earth?

What will be its mass on the surface of the Earth and on the surface of the moon? (Given that [tex]g = 9.8 \, \text{m/s}^2[/tex])

A) 32.67 N, 20 kg, 120 kg
B) 32.67 N, 120 kg, 20 kg
C) 196 N, 20 kg, 120 kg
D) 196 N, 120 kg, 20 kg

The object weighs 32.67 N on the moon and has a mass of 20 kg on both the earth and moon. The weight varies due to the change in gravity, but the mass remains the same.

Explanation:

The weight of the object on the moon would be 32.67 N, and its mass would be 20 kg on both the surface of the earth and the moon. The choice is Option A) 32.67 N, 20 kg, 20 kg.

Weight is determined by the force of gravity on an object. On Earth, if an object has a weight of 196 N, we can determine its mass by dividing by Earth's gravity (9.8 m/s2). This gives us a mass of around 20 kg. Regardless of where the object is, it retains the same mass, because mass is an intrinsic property of the object; it doesn't change with location. Now, the moon's gravity is one-sixth of Earth's. So, the weight of the object on the moon would be its mass times the moon's gravity (which is one-sixth of 9.8 m/s2), which gives us around 32.67 N.

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