High School

The volume of a cylinder is [tex]126 \pi \, \text{ft}^3[/tex], and the radius of the circular base is 6 ft. What is the height of the cylinder?

Given:

\[ V = B \cdot h \]

\[ 126 \pi = (6)^2 (\pi)(h) \]

\[ 126 \pi = 36 \pi (h) \]

\[ 126 = 36(h) \]

Find the value of [tex]h[/tex].

Answer :

To find the height of the cylinder, we start with the formula for the volume of a cylinder:

$$
V = \pi r^2 h
$$

Given that the volume is $126\pi \, \text{ft}^3$ and the radius is $6 \, \text{ft}$, we substitute these values into the formula:

$$
126\pi = \pi (6)^2 h
$$

Since $(6)^2 = 36$, the equation becomes:

$$
126\pi = 36\pi \, h
$$

We can cancel the common factor of $\pi$ from both sides, which simplifies the equation to:

$$
126 = 36 \, h
$$

Next, we solve for $h$ by dividing both sides of the equation by $36$:

$$
h = \frac{126}{36}
$$

Simplifying the fraction gives:

$$
h = 3.5
$$

Thus, the height of the cylinder is $3.5 \, \text{ft}$.