The two insulated beakers shown contain equal amounts of identical liquids. The temperature of Beaker A is 85°C. The temperature of Beaker B is 40°C. A metal rod connects the beakers. Five minutes later, the temperature of Beaker A is 75°C and the temperature of Beaker B is 50°C. What might the temperatures be after another five minutes have passed?

1) Temperature of Beaker A: 64°C. Temperature of Beaker B: 61°C
2) Temperature of Beaker A: 68°C. Temperature of Beaker B: 57°C
3) Temperature of Beaker A: 68°C. Temperature of Beaker B: 48°C
4) Temperature of Beaker A: 68°C. Temperature of Beaker B: 53°C

To determine the temperatures of Beaker A and Beaker B after another five minutes have passed, we can use the principle of thermal equilibrium. In thermal equilibrium, the heat gained by one object is equal to the heat lost by the other object. Since the initial temperature of Beaker A is higher than that of Beaker B, heat will flow from Beaker A to Beaker B.

Assuming that both beakers continue to lose heat at the same rate, Beaker A will cool down by another 10 degrees Celsius, resulting in a temperature of 65°C. Beaker B will also cool down by another 10°C, resulting in a temperature of 40°C. Therefore, the correct answer is:

Temp. of Beaker A - 65°C. Temp. of Beaker B - 40°C