Answer :
Final answer:
The correct hypotheses for testing if BYU-Idaho students sleep more than the national average are H0: μ = 6.2 and Ha: μ > 6.2, where H0 represents the national average and Ha suggests BYU-Idaho students sleep more.
Explanation:
The most appropriate pair of hypotheses for determining whether the mean hours of sleep a night for BYU-Idaho students is higher than the national mean (6.2 hours) is H0: μ = 6.2 and Ha: μ > 6.2. Here, H0 is the null hypothesis which states that the mean hours of sleep for BYU-Idaho students is the same as the national average, which is 6.2 hours. The alternative hypothesis, Ha, suggests that the mean hours of sleep for BYU-Idaho students are greater than the national mean. This setup aligns with the goal of the hypothesis test, which is to gather evidence that could support a claim of BYU-Idaho students sleeping more than the national average.
Answer:
Option A)
[tex]H_{0}: \mu = 6.2\text{ hours}\\H_A: \mu > 6.2\text{ hours}[/tex]
Step-by-step explanation:
We are given he following in the question:
Population mean = 6.2 hours.
The hypothesis wants to determine if the mean hours of sleep a night of students is higher than the national mean.
Thus, we can design the null and alternate hypothesis as:
[tex]H_{0}: \mu = 6.2\text{ hours}\\H_A: \mu > 6.2\text{ hours}[/tex]
The null hypothesis states that mean hours of sleep a night of students is equal to the national mean that is 6.2 hours.
The alternate hypothesis states that mean hours of sleep a night of students is higher than the national mean that is 6.2 hours.
Thus, the correct answer is
Option A)
[tex]H_{0}: \mu = 6.2\text{ hours}\\H_A: \mu > 6.2\text{ hours}[/tex]
