Answer :
The temperature of Place Y at 4000m above sea level is -8°C.
Linear equation
A linear equation is in the form:
y = mx + b
where y, x are variables, m is the rate of change and b is the initial value of y.
Let y represent the temperature above sea level after x thousand meters.
Given that temperature decrease by 6.5 degrees C for every 1000 meters you gain. Hence for 4000m above sea level:
y = -6.5(4) + 18 = -8°C
The temperature of Place Y at 4000m above sea level is -8°C.
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Final answer:
The temperature of Place Y at 4000m above sea level, using the lapse rate of 6.5 degrees Celsius per 1000m, would be -8 degrees Celsius.
Explanation:
The subject at hand is in the realm of environmental or atmospheric physics. It is a known fact that with every 1000m increase in altitude, the temperature decreases by approximately 6.5 degrees Celsius. This is called the lapse rate. Using this formula, if Place Y is 4000m above sea level, then the temperature would decrease by approximately 26 degrees Celsius (4 x 6.5). However, the temperature at sea level is 18 degrees. Subtracting our calculated decrease from the sea level temperature, the temperature of Place Y at 4000m above sea level would be -8 degrees Celsius.
Learn more about Lapse Rate here:
https://brainly.com/question/14394445
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