Answer :
Final answer:
The heat capacity of the object is 95.8 J/°C.
Explanation:
The heat capacity (C) of an object is the quantity of heat (q) it absorbs or releases when it experiences a temperature change (ΔT) of 1 degree Celsius (or equivalently, 1 kelvin). To calculate the heat capacity, we can use the formula:
C = q/ΔT
In this case, we know that the object absorbed 3647 J of heat and its temperature increased by 38.1 °C. Plugging these values into the formula:
C = 3647 J / 38.1 °C = 95.8 J/°C
Therefore, the heat capacity of the object is 95.8 J/°C.
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The heat capacity of an object is defined as the amount of heat required to raise its temperature by 1 degree Celsius (or 1 Kelvin). It is denoted by the symbol "C" and has units of J/°C (Joules per degree Celsius) or J/K (Joules per Kelvin).
We can use the formula for heat capacity to calculate its value for the object:
- [tex]C = \dfrac{Q}{\Delta T}[/tex]
where:
- Q is the amount of heat absorbed by the object and
- ΔT is the change in temperature of the object.
Substituting the given values, we get:
- [tex]C = \dfrac{3647 \: J }{ 38.1\: ^{\circ}C}[/tex]
Note that the units of temperature must match (either Celsius or Kelvin) in order for the calculation to be correct. Since the given change in temperature is in Celsius, we can use Celsius for the units of heat capacity as well.
Dividing, we get:
- [tex]C = 95.8 \: J/^{\circ}C[/tex]
Therefore, the heat capacity of the object is 95.8 J/°C. This means that it requires 95.8 Joules of heat to raise the temperature of the object by 1 degree Celsius (or Kelvin).
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