Answer :
Final answer:
The value of the force on panel AB after the acceleration is 34.6 Newtons.
Explanation:
In order to determine the force on panel AB after acceleration, we need to know the volume of the liquid in the tank and its density. The volume of a cuboid is given by length x width x height. In this case, the volume V of the liquid would be 12cm * 38.8cm * 11.8cm = 5486.08 cubic cm.
Next, convert this volume to cubic meters by dividing by 1,000,000 (since there are 1,000,000 cubic centimeters in a cubic meter), giving us 0.00548608 m^3.
We're not given the specific liquid, but if we assume the liquid is water (density = 1000 kg/m^3), the mass m of the water in the tank would be density x volume = 1000 kg/m^3 * 0.00548608 m^3 = 5.48608 kg.
The force exerted by the water on the wall when the tank accelerates to the right is given by F = m * a, where a is the acceleration. Given an acceleration of 6.3 m/s^2, the force F = 5.48608kg * 6.3 m/s^2 = 34.582104 N. Hence, the force on panel AB is approximately 34.6 Newtons.
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