Answer :
Final answer:
The heat needed to raise the temperature of a 0.015 kg sample of lead by 10°C is 19.2 joules.
Explanation:
To calculate the amount of heat needed to raise the temperature of a 0.015 kg sample of lead by 10°C, you can use the formula
Q = mcΔT,
where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
Using the given values, the specific heat (c) of lead is 128 J/kg.°C, the mass (m) is 0.015 kg, and the temperature change (ΔT) is 10°C.
Plugging in the numbers, we get
Q = (0.015 kg) × (128 J/kg.°C) × (10°C)
= 19.2 J.
Hence, 19.2 joules of heat is needed to achieve the desired temperature increase for the lead sample.
