High School

The specific heat capacity of solid platinum is 0.133 J/g°C.

(a) Determine the amount of heat energy that is associated with heating a 10.1-g sample of solid platinum from 23.0 °C to 37.1 °C.

(b) Calculate the heat energy in joules (J).

Answer :

(a) The amount of heat energy: 18.0043 J.

(b) The final temperature: 71.36 °C

(a) Calculation for the amount of heat energy:

The equation to calculate the amount of heat energy is Q = mcΔT

where,

Q is the heat energy

m is the mass of the platinum

c is the specific heat capacity of the platinum

ΔT is the change in temperature.

Substitute the given values into the equation:

Q = 10.1 g × 0.133 J/g °C × (37.1 °C - 23.0 °C)

Q = 10.1 g × 0.133 J/g °C × 14.1 °C = 18.0043 J.

(b) Calculation for the final temperature:

Use the equation Q = mcΔT, but this time solve for ΔT.

Rearrange the equation: ΔT = Q / mc

Substitute the given values into the equation:

ΔT = 121 J / (18.8 g × 0.133 J/g °C)

ΔT = 121 J / 2.5024 J/°C ≈ 48.36 °C

Finally, add the change in temperature to the initial temperature: 23.0 °C + 48.36 °C = 71.36 °C

To learn more about Heat energy:

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