Answer :
The concentration of Ag⁺ ion in a saturated solution of Ag₃PO₄ is 4.65 x 10⁻⁵ M.
The correct answer is c. 4. 65 x 10⁻5 M
Write the dissociation equation:
The dissociation equation for silver phosphate is:
Ag₃PO₄(s) ⇌ 3Ag⁺(aq) + PO₄³⁻(aq)
Write the solubility product expression:
The solubility product expression for Ag₃PO₄ is:
Ksp = [Ag⁺]³ [PO₄³⁻]
Given that Ag₃PO₄ is sparingly soluble, we can approximate [Ag⁺] ≈ 3[Ag₃PO₄]
Plug in the given solubility:
Given: [Ag₃PO₄] = 1.55 x 10⁻⁵ M
Therefore, [Ag⁺] ≈ 3 * 1.55 x 10⁻⁵ M = 4.65 x 10⁻⁵ M
Verify the answer:
The closest answer choice is 4.65 x 10⁻⁵ M, which matches our calculated value.
Therefore, the correct answer is option (c) 4.65 x 10⁻⁵ M.