High School

The solubility of silver phosphate, Ag₃PO₄, at 25°C is 1.55 x 10⁻⁵ mol/L. Determine the concentration of the [tex]$\text{Ag}^+$[/tex] ion in a saturated solution.

A. 3.72 x 10⁻¹⁵ M
B. 1.94 x 10⁵ M
C. 4.65 x 10⁻⁵ M
D. 1.55 x 10⁻⁵ M
E. 5.17 x 10⁻⁶ M

Answer :

The concentration of Ag⁺ ion in a saturated solution of Ag₃PO₄ is 4.65 x 10⁻⁵ M.

The correct answer is c. 4. 65 x 10⁻5 M

Write the dissociation equation:

The dissociation equation for silver phosphate is:

Ag₃PO₄(s) ⇌ 3Ag⁺(aq) + PO₄³⁻(aq)

Write the solubility product expression:

The solubility product expression for Ag₃PO₄ is:

Ksp = [Ag⁺]³ [PO₄³⁻]

Given that Ag₃PO₄ is sparingly soluble, we can approximate [Ag⁺] ≈ 3[Ag₃PO₄]

Plug in the given solubility:

Given: [Ag₃PO₄] = 1.55 x 10⁻⁵ M

Therefore, [Ag⁺] ≈ 3 * 1.55 x 10⁻⁵ M = 4.65 x 10⁻⁵ M

Verify the answer:

The closest answer choice is 4.65 x 10⁻⁵ M, which matches our calculated value.

Therefore, the correct answer is option (c) 4.65 x 10⁻⁵ M.