Answer :
Final answer:
The total solar energy incident on the panels in 1 hour is calculated by multiplying the incident power per square meter by the total area of the panels and the time in seconds. This yields a result of approximately 4.896 million Joules.
Explanation:
The student is asking how much solar energy hits a solar panel with an area of 8.0 m² in an hour if the solar power incident on the roof is 170 W/m².
To calculate this, we need to multiply the power incident per square meter (170 W/m²) by the total area (8.0 m²) to get the total power that falls on the panels. The result represents the power per second (in Watts), and since energy is power multiplied by time, we need to multiply this by the number of seconds in an hour (3600) to get the energy in Joules. Hence, the calculation is:
Total Power = Power incident per square meter * Total area = 170 W/m² * 8.0 m² = 1360 W
Energy = Total Power * Time = 1360 W * 3600 s = 4.896 * 10^6 Joules
Thus, the total solar energy falling on the solar panels in one hour is approximately 4.896 million Joules.
Learn more about Solar Energy Calculation here:
https://brainly.com/question/14566365
#SPJ11
