The perimeter of a rectangle is 120 meters. If the length of the rectangle is 20 meters more than the width, what are the dimensions of the rectangle?

Question

High School

Answer :

wacko37 wacko37 · Answer 1 · 2024-04-04T05:49:13-04:00

120= 2(w+20) + 2w
120= 2w+40+2w
120= 40+4w
80=4w
w=20
Length:
w+20
20+20
40
Width: 20
So the dimensions are:
Length is 40
Width is 20

Answer Link

rairicha556 rairicha556 · Answer 2 · 2023-08-08T02:37:13-04:00

Rectangle with perimeter 120m has its length and breadth 40 m and 20 m respectively.

Dimension of rectangle : 40 × 20

Given, that perimeter of rectangle is 120 m.

Now, perimeter of rectangle is given by:

P = 2(l+b)

l = Length of rectangle .

b = Breadth of rectangle.

Let the breadth of rectangle be 'x' m.

Then length will be (x+20) m.

Substitute the values in the perimeter formula,

[tex]P = 2(l+b)\\120 = 2(x+20 + x)\\120 = 2(2x + 20)\\60 = 2x + 20\\x = 20[/tex]

Thus the breadth of rectangle is 20 m.

Length of rectangle is 20 m more than the breadth.

Length = 20 + 20

Length = 40 m.

Therefore the dimensions of rectangle is 40 × 20.

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