Answer :
To determine the amount of KCl to be added, we start by calculating the concentration of KCl in the ampule. The ampule contains [tex]$40$[/tex] mEq of KCl in a volume of [tex]$20$[/tex] mL, so the concentration is given by
[tex]$$
\text{Concentration} = \frac{40\text{ mEq}}{20\text{ mL}} = 2\text{ mEq/mL}.
$$[/tex]
Next, the order requires [tex]$20$[/tex] mEq of KCl. To find the volume of KCl solution needed, we use the concentration:
[tex]$$
\text{Volume} = \frac{20\text{ mEq}}{2\text{ mEq/mL}} = 10\text{ mL}.
$$[/tex]
Thus, [tex]$10$[/tex] mL of the KCl solution should be added to the [tex]$500$[/tex] mL of D5W.
[tex]$$
\text{Concentration} = \frac{40\text{ mEq}}{20\text{ mL}} = 2\text{ mEq/mL}.
$$[/tex]
Next, the order requires [tex]$20$[/tex] mEq of KCl. To find the volume of KCl solution needed, we use the concentration:
[tex]$$
\text{Volume} = \frac{20\text{ mEq}}{2\text{ mEq/mL}} = 10\text{ mL}.
$$[/tex]
Thus, [tex]$10$[/tex] mL of the KCl solution should be added to the [tex]$500$[/tex] mL of D5W.
