High School

The normal boiling point of liquid methanol is 338 K. Assuming that its molar heat of vaporization is constant at 38.8 kJ/mol, what is the boiling point of [tex] \text{CH}_3\text{OH} [/tex] when the external pressure is 0.730 atm?

Answer :

The boiling point of methanol when the external pressure is 0.730 atm is 378.78 K

T₁=338K

ΔH=38.8kJ/mol

P₁=1atm

P₂=0.73atm

we know that,

ln (P₂/P₁)=ΔH/R(1/T₁-1/T₂)

where,

T₁ is initial temperature

T₂ is final temperature

P₁ is initial pressure

P₂ is final pressure

on substituting value we get

T₂ = 378.78 K

learn more about pressure vs temperature here:

https://brainly.com/question/4674548

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