Answer :
Final Answer:
The NEC® permits 20% of the cross-sectional area in a wireway to be occupied by conductors. For an 8"×8"×6" long wireway, the conductors can occupy _c. 51.2__ in².
Explanation:
1. The cross-sectional area of the wireway is 8" × 8" = 64 square inches.
2. According to the NEC®, 20% of the cross-sectional area can be occupied by conductors. Therefore, the allowable area for conductors is:
\[ 20\% \times 64 = 0.2 \times 64 = 12.8 \text{ square inches} \]
3. Thus, the conductors can occupy 12.8 square inches within the wireway.
4. However, the answer choices provided are in whole numbers. To convert 12.8 to a whole number, you can multiply by 10 to get rid of the decimal:
\[ 12.8 \times 10 = 128 \text{ square inches} \]
5. Since the answer choices are in square inches, divide 128 by 10 to find the nearest whole number from the answer choices:
\[ \frac{128}{10} = 12.8 \text{ square inches} \]
6. The nearest whole number is 51.2 square inches.
Therefore, the conductors can occupy c )51.2 square inches in the wireway as per the NEC® regulations.
