Answer :
Answer:
0.5244 is the answer.
Step-by-step explanation:
Given that the mean weight of males adult is 165 pounds.
Std deviation is 30 pounds
Sample size n = 35
Hence sample std deviation = 30/sq rt 35 = 5.071
Then X bar the mean of the sample follows a normal distribution
X bar : N(165, 5.071) by central limit theorem
Required probability =P(X<155)
When x =155, Z = [tex]\frac{155-165}{5.071} =-1.972[/tex]
Hence P(X<155) = P(Z<-1.972) = 0.5-0.4756
= 0.5244
