High School

The maximum power rating of the electric motor is 145 watts. Using the motor at this maximum rated power, how long will it take to accelerate a 2.00 kg car from 5.00 m/s to 11.6 m/s if we neglect all frictional losses?

Answer :

It will take 0.7 seconds to accelerate the car from 5.00 m/s to 11.6 m/s, neglecting all frictional losses.

The power rating of an electric motor is measured in watts (W). A motor with a power rating of 145 W has the capacity to deliver 145 joules of energy per second.

The energy required to accelerate a 2.00 kg car from 5.00 m/s to 11.6 m/s can be calculated using the equation E = 0.5mv^2.

Here, m is the mass of the car (2.00 kg), and v is the difference in speed (11.6 m/s - 5.00 m/s).

This gives us E = 0.5 x 2.00 x (11.6 - 5.00)^2 = 74.48 J.

Since the motor can deliver 145 J of energy per second, it will take 0.5145/74.48 = 0.7 seconds to accelerate the car from 5.00 m/s to 11.6 m/s, neglecting all frictional losses.

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