Answer :
The frequency of a 20-inch violin string is approximately 642.86 cycles per second.
What is Frequency ?
Frequency is a measure of the number of cycles or oscillations of a periodic event per unit of time. It is usually measured in hertz (Hz), which represents the number of cycles per second.
We can use the inverse variation formula, which states that:
Length of string ∝ 1/frequency
where ∝ means "is proportional to".
We can write this as:
Length of first string / Length of second string = Frequency of second string / Frequency of first string
Let L1 be the length of the first string (14 inches) and f1 be the frequency of the first string (450 cycles per second). Let L2 be the length of the second string (20 inches) and f2 be the frequency of the second string (which we need to find).
Plugging in the values we know, we get:
L1 / L2 = f2 / f1
Solving for f2, we get:
f2 = (L2 / L1) x f1
Substituting the given values, we get:
f2 = (20 / 14) x 450
f2 = 642.86 (rounded to two decimal places)
Therefore, the frequency of a 20-inch violin string is approximately 642.86 cycles per second.
To learn more about Frequency from given link.
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