Answer :
Final answer:
To answer these questions, we use the normal distribution and R programming. We calculate z-scores to find probabilities and to determine cutoff points. We can use the 'qnorm' function in R to find values corresponding to specific percentiles. The z-score of 0.89 means the length of the stem is 0.09 standard deviations longer than the average rose stem.
Explanation:
To answer these questions, we can use the normal distribution. Let's break down each question:
a. To find the probability that a given rose stem will be shorter than 21.9 inches, we need to calculate the z-score and find the corresponding probability using R. The formula to calculate the z-score is:
z = (x - mean) / standard deviation
where x is the given value, mean is the mean length of rose stems, and standard deviation is the standard deviation of rose stem lengths. Using R, we can calculate the z-score and find the probability that a rose stem will be shorter than 21.9 inches.
b. To find the probability that a given rose will be considered a long stem rose (stem length > 24 inches), we follow a similar process as in part a. Calculate the z-score and find the probability.
c. To find the maximum stem length that qualifies to be used as a corsage, we need to find the value of x (stem length) that corresponds to the 6th percentile. We can use R to find this value by first calculating the z-score using the formula mentioned earlier, and then using the 'qnorm' function in R to find the corresponding value of x.
d. The z-score of 0.89 tells us that the length of this stem is 0.09 standard deviations longer than the average rose stem. So, the correct interpretation is option C.
Learn more about Normal Distribution here:
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