Answer :
The width of the rectangular swimming pool, given that its length is twice its width and the perimeter is 120 feet, is 20 feet.
The subject of this question is in the area of Mathematics, specifically, in algebra and geometry. The problem involves determining the width of a rectangular swimming pool given that the length of the rectangular swimming pool is twice the width and the perimeter is 120 feet. According to the problem, if we let w be the width, the length will be 2w.
The formula for the perimeter of a rectangle is 2 * (length + width). Substituting the values we get 2 * (w + 2w) = 120.
Solving this equation, we get 3w=60, and therefore, w=20 feet. So, the width of the pool is 20 feet.
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The perimeter of a rectangle is the sum of its sides, which are two widths and two lengths:
[tex]p=w+w+l+l[/tex]
Since the length is twice the width, we have [tex]l=2w[/tex], and the formula for the perimeter becomes
[tex]p=w+w+2w+2w=6w[/tex]
So, we have
[tex]6w=120 \iff w=\dfrac{120}{6}=20[/tex]
