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------------------------------------------------ The length of a rectangle is twice the width. The perimeter is 126 centimeters.

Which system of equations will determine the length, [tex]L[/tex], and the width, [tex]W[/tex], of the rectangle?

A. [tex]L + 2 = W[/tex]
[tex]2L + 2W = 126[/tex]

B. [tex]L + W = 2[/tex]

C. [tex]L = 2W[/tex]
[tex]2L + 2W = 126[/tex]

D. [tex]W = 2L[/tex]
[tex]L + 2W = 126[/tex]

E. [tex]2L = W[/tex]
[tex]L + W = 126[/tex]

Answer :

To solve this problem, we need to formulate a system of equations based on the information provided about the rectangle.

1. Understand the problem:
- You have a rectangle with a length (L) and a width (W).
- The length is twice the width.
- The perimeter of the rectangle is 126 centimeters.

2. Translate the information into equations:
- Since the length is twice the width, we can express this relationship as:
[tex]\[
L = 2W
\][/tex]
- The formula for the perimeter [tex]\( P \)[/tex] of a rectangle is:
[tex]\[
P = 2L + 2W
\][/tex]
We know the perimeter is 126 centimeters, so:
[tex]\[
2L + 2W = 126
\][/tex]

3. Form the system of equations:
Combining the two equations we derived:
[tex]\[
\begin{align*}
L &= 2W \\
2L + 2W &= 126
\end{align*}
\][/tex]

4. Identify the correct option:
- Looking at the options, we search for the system of equations that matches:
- [tex]\( L = 2W \)[/tex]
- [tex]\( 2L + 2W = 126 \)[/tex]

The correct option is:
- Option C:
[tex]\[
\begin{align*}
L &= 2W \\
2L + 2W &= 126
\end{align*}
\][/tex]

Therefore, the correct system of equations is given in option C.