Answer :
Final answer:
The patient would use 3 single-use containers of the potassium chloride solution per day. This is calculated based on the requirement of 30 mEq dose twice a day.
Explanation:
The subject of this question is related to dosage calculation, which falls under the broad field of medicine. The problem can be solved by applying simple math. The medication provides 20 mEq in 15 mL of solution. So, for 30 mEq (the required dose per time), you would need 1.5 times the volume of the solution that contains 20 mEq, which is 22.5 mL. Since you're giving the medication twice a day, the total volume of solution used in a day is 2 * 22.5 = 45 mL. Each single-use container is 15 mL, so you would need 45 / 15 = 3 single-use containers in a day.
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