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------------------------------------------------ The jet fuel in an airplane has a mass of 97.5 kg and a density of 0.804 g/cm³.

What is the volume of this jet fuel?

\[ d = \frac{m}{v} \]

Answer :

The volume of the jet fuel with a mass of 97.5 kg and a density of 0.804 g/cm³ is approximately 121.28 liters.

To calculate the volume of the jet fuel, we can use the formula for density:

density (ρ) = mass (m) / volume (v)

Rearranging the formula to solve for volume, we have:

volume (v) = mass (m) / density (ρ)

The mass of the jet fuel is 97.5 kg and the density is 0.804 g/cm³, we need to convert the density to the appropriate units. Since the given mass is in kilograms, we'll convert the density to kg/cm³ as well.

0.804 g/cm³ = 0.804 × 10³ kg/m³ = 804 kg/m³

Now we can substitute the values into the formula:

volume (v) = 97.5 kg / 804 kg/m³

Simplifying the equation:

volume (v) = 0.12128 m³

To convert the volume to liters, we multiply by 1000:

volume (v) = 0.12128 m³ × 1000 = 121.28 liters

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