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------------------------------------------------ The hot resistance of a light bulb rated at 60 W, 120 V is:

A. 120 ohms
B. 220 ohms
C. 140 ohms
D. 240 ohms
E. 220 ohms

Answer :

The hot resistance of a light bulb rated 60 W, 120 V is 240 ohms. This is calculated using the formula R = V²/P, where R is the resistance, V is the voltage, and P is the power.

The hot resistance of a light bulb can be calculated using the formula:

R = V²/P

where R is the resistance, V is the voltage, and P is the power.

In this case, the power rating is 60 W and the voltage is 120 V. Plugging in these values, we get:

R = (120 V)² / 60 W

R = 14400 V²/W / 60 W

R = 240 ohms

Therefore, the hot resistance of the light bulb rated 60 W, 120 V is 240 ohms.

So the answer is (d) 240 ohms.

Learn more about resistance here: brainly.com/question/11431009

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