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------------------------------------------------ The figure below shows a square ABCD and an equilateral triangle DPC:

ABCD is a square. P is a point inside the square. Straight lines join points A and P, B and P, D and P, and C and P. Triangle D

Ted makes the chart shown below to prove that triangle APD is congruent to triangle BPC:

Statements Justifications

In triangles APD and BPC; DP = PC Sides of equilateral triangle DPC are equal

In triangles APD and BPC; AD = BC Sides of square ABCD are equal

In triangles APD and BPC; angle ADP = angle BCP Angle ADC = angle BCD = 90° so angle ADP = angle BCP = 60°

Triangles APD and BPC are congruent SAS postulate

What is the error in Ted's proof? (1 point)

He writes the measure of angles ADP and BCP as 60° instead of 45°.

He uses the SAS postulate instead of AAS postulate to prove the triangles congruent.

He writes the measure of angles ADP and BCP as 60° instead of 30°.

He uses the SAS postulate instead of SSS postulate to prove the triangles congruent.

In the square ABCD, the diagonals AC and BD intersect at point P, dividing the square into four right triangles. Since the diagonals of a square are equal and bisect each other, AP = BP = CP = DP. Also, since the diagonals of a square are perpendicular bisectors, ∠APD = ∠BPC = 45°, not 60°.

Therefore, the correct statement should be: “Angle ADC = angle BCD = 90° so angle ADP = angle BCP = 45°”.