High School

The far point of a myopic eye is 1.5 m. To correct this defect, what is the power of the lens needed?

A. 0.66 D
B. -0.66 D
C. +1.5 D
D. -1.55 D

Answer :

Final answer:

To correct myopia, a diverging lens is used. The power of the lens can be calculated using the formula Power = 1 / focal length. The correct power in this case is 0.66 D.

Explanation:

To correct the defect of myopia, a diverging lens is used. The power of the lens can be found using the formula:
Power (in diopters) = 1 / focal length (in meters)

Given that the far point of the myopia lens is 1.5 m, we can find the power of the lens:

Power = 1 / 1.5 = 0.67 D

Therefore, the correct option is (a) 0.66 D.

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