The erythropoietin protein is 193 amino acids long. That means the number of nucleic acids in the mRNA molecule, including the initiator and terminator codons, are:

a) 65
b) 193
c) 582
d) 579

The correct answer is (c) 582.The genetic code is comprised of a sequence of three nucleotides, or a codon, which specifies a particular amino acid.

Since the erythropoietin protein is composed of 193 amino acids, the number of nucleotides in the mRNA molecule would be the product of the number of amino acid and the number of nucleotides per codon, which is three. Additionally, we must account for the initiator codon (AUG) and the terminator codon (UAA, UAG, or UGA).

Therefore, the total number of nucleotides in the erythropoietin mRNA molecule would be: 193 (amino acids) x 3 (nucleotides per codon) + 3 (initiator codon) + 3 (terminator codon) = 582 nucleotides

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The erythropoietin protein is 193 amino acids long. That means the number of nucleic acids in the mRNA molecule, including the initiator and terminator codons, are:a) 65 b) 193 c) 582 d) 579

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The erythropoietin protein is 193 amino acids long. That means the number of nucleic acids in the mRNA molecule, including the initiator and terminator codons, are:

a) 65
b) 193
c) 582
d) 579