Answer :
The energy released during an earthquake can be calculated using the formula [tex]E = 10^(^1^1^.^8^ +^ 1^.^5^M^)[/tex], where M is the earthquake's magnitude on the Richter scale. If M = 5, for instance, the energy release would be [tex]E = 10^1^9^.^3[/tex] joules.
The question seems to be asking about earthquake intensity, expressed using the Richter scale, and how it relates to the amount of energy released during the earthquake. However, it's a little difficult to understand as there are many irrelevant parts of the question.
Given the formula [tex]log(E) = 11.8 + 1.5M[/tex], where E is the energy released in joules and M is the Richter scale magnitude, you can solve for E by rearranging the formula to get [tex]E = 10^(^1^1^.^8^ +^ 1^.^5^M^)[/tex] joules.
Suppose M = 5 for an earthquake of magnitude 5 on the Richter scale, then the energy, [tex]E = 10^(^1^1^.^8^+^1^.^5^*^5^)[/tex] = [tex]10^1^9^.^3[/tex] joules would be the energy released by that earthquake. This is a detailed explanation to understand the relationship between Richter scale magnitude and energy released during an earthquake.
Learn more about Richter scale here:
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Complete question is:
The energy Ensured in Joules roased by an earthquake of the Riderscale Mog (a) What was the intensity of the earth? (how many of energy was released © k given by the equation log+441 SM)
