High School

The element radon is at the opposite end of the range, with the lowest specific heat of all naturally occurring elements. Radon's specific heat is 94 J/kg°C.

If the temperature of a 0.34 kg sample of radon is to be raised by 25°C, how much energy will have to be added to the radon?

Answer :

Explanation:

Q = mc∆T

= (0.34 kg)(94 J/kg-°C)(25°C)

= 799 J

Final answer:

The energy required to raise the temperature of a 0.34 kg sample of radon by 25°C is 799.5 J.

Explanation:

The specific heat of a substance determines the amount of energy required to raise its temperature by a certain amount. In this case, we are given the mass of radon (0.34 kg), its specific heat (94 J/kg°C), and the change in temperature (25°C). To calculate the energy required, we can use the formula:

Energy = mass × specific heat × change in temperature

Plugging in the values, we have:

Energy = 0.34 kg × 94 J/kg°C × 25°C = 799.5 J

Therefore, the amount of energy that needs to be added to the radon sample is 799.5 joules.

Learn more about specific heat here:

https://brainly.com/question/31608647

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