Answer :
Final answer:
In this direct variation scenario, by finding the constant of variation with the initial given values, we can predict the distance a spring would stretch under a new weight. By applying these calculations, we find that a spring stretched by a 13-kg object would stretch approximately 26 cm.
Explanation:
The scenario described in your question is an example of direct variation, where the distance, d, that a spring is stretched varies directly with the weight, w. We can write this as a mathematical equation: d = kw, where k is the constant of variation.
We can find 'k' with the given information, where a 27-kg object stretches the spring 53 cm. This gives us: k = d/w = 53/27.
Once we have found 'k', we can find the distance the spring is stretched by a 13-kg object: d = kw = (53/27) * 13. Rounded to the nearest whole centimeter, we find the distance to be approximately 26 cm.A) 26 cm is the correct answer.
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