High School

The combined SAT scores for the students at a local high school are normally distributed with a mean of 1504 and a standard deviation of 304. The local college includes a minimum score of 2385.6 in its admission requirements.

What percentage of students from this school earn scores that satisfy the admission requirement?

Answer :

The percentage of students from the local high school who satisfy the admission requirement is approximately 99.71%.

To determine the percentage of students from the local high school who satisfy the admission requirement of a local college, we need to find the percentage of students whose SAT scores are equal to or higher than the minimum score of 2385.6.

First, we need to calculate the z-score using the formula: z = (x - μ) / σ, where x is the SAT score, μ is the mean, and σ is the standard deviation.

Once we have the z-score, we can use a standard normal distribution table or calculator to find the percentage of students with z-scores equal to or greater than the calculated z-score.

Let's assume a student's SAT score is 2385.6. Using the formula, we calculate the z-score: z = (2385.6 - 1504) / 304 = 2.902.

When we look up the z-score in the standard normal distribution table or calculator, we find that approximately 99.71% of the students have SAT scores less than or equal to 2385.6.

Therefore, the percentage of students from the local high school who satisfy the admission requirement is approximately 99.71%.

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