The combined SAT scores for students at a local high school are normally distributed with a mean of 1524 and a standard deviation of 298. The local college requires a minimum score of 809 for admission. What percentage of students from this school earn scores that fail to satisfy the admission requirement?

To find the percentage of students who fail to satisfy the admission requirement, we need to calculate the z-score for the minimum score and use a z-table or calculator.

Explanation:

To find the percentage of students from this school who earn scores that fail to satisfy the admission requirement, we need to calculate the z-score for the minimum admission requirement score. The z-score formula is given by z = (X - μ) / σ, where X is the score we want to convert to a z-score, μ is the mean of the distribution, and σ is the standard deviation. Plugging in the values, we have z = (809 - 1524) / 298 ≈ -2.24. We can then use a z-table or a calculator to find the percentage of scores below the z-score of -2.24, which represents the percentage of students who fail to satisfy the admission requirement.

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