High School

The chloride of a metal contains 71% chlorine by weight, and the vapor density is 50. What is the atomic weight of the metal?

A. 29
B. 58
C. 35.5
D. 71

Answer :

Final answer:

To find the atomic weight of the metal in a compound with 71% chlorine and a vapor density of 50, calculate the molecular weight and subtract the mass of chlorine. Use the mass and moles of metal to compute the atomic weight, and compare it with the given options.

Explanation:

To determine the atomic weight of the metal in the metal chloride that contains 71% chlorine by weight, and with a vapor density of 50, one can use the concept of vapor density and the percentage by weight. Vapor density is related to molecular weight by the formula:

Vapor Density = Molecular Weight / 2

Considering the vapor density given as 50, the molecular weight (M) of the metal chloride can be calculated:

M = Vapor Density times 2 = 50 imes 2 = 100 g/mol

Since chlorine accounts for 71% by weight in the compound, we can determine the mass of chlorine in one mole of the compound:

Mass of Cl = 71/100 times 100 g/mol = 71 g/mol

Using the atomic mass of chlorine (35.45 g/mol), the moles of Cl in the compound can be calculated:

Moles of Cl = 71 g / 35.45 g/mol

The mass of metal can then be found by subtracting the mass of Cl from the molecular weight of the compound, and using the result to obtain the atomic weight of the metal:

Mass of Metal = Molecular Weight of Metal Chloride - Mass of Cl

Atomic Weight of Metal = Mass of Metal / Moles of Metal

By completing these calculations, one can identify the correct atomic weight from the given options.