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------------------------------------------------ The angular speed of an automobile engine is increased at a constant rate from 1200 rev/min to 3000 rev/min in 12 seconds.

(a) What is its angular acceleration in revolutions per minute squared?

(b) How many revolutions does the engine make during this 12-second interval?

Answer :

a) The angular acceleration of the automobile is 9000 rev/min².

b) The engine makes 420 revolution during this 12 s interval.

What is angular acceleration?

The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per second per second.

Rotational acceleration is another name for angular acceleration. It is a numerical representation of the variation in angular velocity over time.

Initial angular speed = 1200 rev/min.

Final angular speed = 3000 rev/min.

Time taken = 12 second = 0.2 minute.

a) its angular acceleration is = (final angular speed - Initial angular speed )/ Time taken

= ( 3000 rev/min - 1200 rev/min)/0.2 minute

= 9000 rev/min²

b) The engine makes during this 12 s interval = (Initial angular speed + Final angular speed) × time interval/2

= (1200 + 3000)× 0.2/2 revolution

= 420 revolution.

Learn more about angular acceleration here:

https://brainly.com/question/29428475

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Answer:

The angular acceleration is

=

15.71

r
a
d
s
− 2 and the number of revolutions is =
419.9

Explanation:

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