Answer :
Final answer:
The addition of more light bulbs in a parallel circuit leads to a decrease in total resistance and an increase in total current. An ammeter would see an increase in total current with the addition of each bulb. Identical bulbs in a parallel circuit draw the same current, so in this example, another parallel lamp would also have a current of 900 mA or 0.9 A.
Explanation:
When adding more light bulbs in parallel to an electrical circuit, the total resistance in the circuit decreases because each added path allows for more current to flow. The ammeter, a device used to measure current, would show an increase in the total current with each additional bulb.
If, hypothetically, the ammeter initially reads 186 mA, then in order to calculate the current in another parallel lamp, one would need the total voltage and resistance of the system.
Assuming all lamps are identical and using Ohm's law (V = IR), the current through each individual lamp can be calculated once the total current and resistance are known.
If a typical light bulb has a current draw of 900 mA from a 110 V source, we can calculate its resistance using Ohm's law.
The resistance (R) is given by the voltage (V) divided by the current (I), hence R = V/I.
In this case, R = 110 V / 0.9 A (since 900 mA is equal to 0.9 A), which gives us a resistance of 122.22 ohms for the light bulb.
If multiple identical bulbs are added in parallel, the resistance of each bulb remains the same, but the total current increases.
The final value for the current in another parallel lamp will be the same as the initial reading if it is assumed that the lamps are identical.
Therefore, the second lamp would also draw a current of 900 mA, which is equivalent to 0.9 A, just like the first lamp.
In a parallel circuit, all components have the same voltage across them and draw current based on their resistance.
