High School

The A string on a violin has a fundamental frequency of 440 Hz. The length of the vibrating portion is 30.8 cm, and it has a mass of 0.343 g. Under what tension must the string be placed?

Answer :

Tension must the string be placed is 86.75 N.

What is Tension?

In physics, tension is defined as the pulling force that is transmitted axially by a string, rope, chain, or similar object, or by each end of a rod, truss member, or other comparable three-dimensional object. Tension can also be defined as the action-reaction pair of forces acting at each end of the aforementioned elements.

f = 440 Hz

l = 32 cm = 0.32 m

m = 0.35 g = 0.35 x 10^-3 kg

μ = m / l = 0.35 x 10^-3 / 0.32 = 1.094 x 10^-3 kg/m

The formula for the fundamental frequency is given by

[tex]f=\frac{1}{2 l} \sqrt{\frac{T}{\mu}}$$[/tex]

Where, T be the tension

[tex]$$\begin{aligned}& 440=\frac{1}{2 \times 0.32} \sqrt{\frac{T}{1.094 \times 10^{-3}}} \\& 281.6=\sqrt{\frac{T}{1.094 \times 10^{-3}}}\end{aligned}$$[/tex]

T = 86.75 N

Thus, the tension in the string is 86.75 N.

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