Answer :
Answer:T=[tex]2.27\times 10^{-3}[/tex]
Explanation:
Given the frequency of tuning fork be 440 HZ
let the frequency of Violin string be F
beat frequency =F-440 =5
therefore
F=445 Hz
Period of oscillation of string=[tex]\frac{1}{F}[/tex]
[tex]T=2.27\times 10^{-3} s[/tex]
Answer:
2.232×10⁻³ seconds
Explanation:
Number of beats with respect to time = 5 beats/s
F = String is oscillating at 4.4×10² Hz
A beat is a pattern of interference between two different frequencies.
[tex]\text{Beat frequency}=\frac{1}{T}-F\\\Rightarrow 5=\frac{1}{T}-440\\\Rightarrow \frac{1}{T}=445\\\Rightarrow T=\frac{1}{445}\\\Rightarrow T=0.002247\ s[/tex]
Time periods is 2.247×10⁻³ seconds
