High School

The A string of a violin is a little too tightly stretched. Beats at 5 per second are heard when the string is sounded together with a tuning fork that is oscillating accurately at concert A (4.40 × 10^2 Hz). What is the period of the violin string oscillation?

Answer :

Answer:T=[tex]2.27\times 10^{-3}[/tex]

Explanation:

Given the frequency of tuning fork be 440 HZ

let the frequency of Violin string be F

beat frequency =F-440 =5

therefore

F=445 Hz

Period of oscillation of string=[tex]\frac{1}{F}[/tex]

[tex]T=2.27\times 10^{-3} s[/tex]

Answer:

2.232×10⁻³ seconds

Explanation:

Number of beats with respect to time = 5 beats/s

F = String is oscillating at 4.4×10² Hz

A beat is a pattern of interference between two different frequencies.

[tex]\text{Beat frequency}=\frac{1}{T}-F\\\Rightarrow 5=\frac{1}{T}-440\\\Rightarrow \frac{1}{T}=445\\\Rightarrow T=\frac{1}{445}\\\Rightarrow T=0.002247\ s[/tex]

Time periods is 2.247×10⁻³ seconds