Answer :
Each support exerts upward forces of 751.33 N and 1012.67 N on the beam.
We use the principle of moments to determine the upward force that the beam is producing.
From the attached diagram,
Let's talk briefly about N2.
Equation 1: Mgd1+ Mgd2 = N2L Where:
M stands for beam mass.
d1 represents the beam's middle.
Student mass is equal to m, and student distance from N2 is equal to d2.
N2 is support. 2
L stands for "beam length."
g stands for gravitational acceleration.
Considering the query,
M = 94 kg, m = 86 kg, d1 = 1.5 m, d2, 1 m, L, 3 m, g, 9.8 m/s2,
Equation 1 can be solved for N2 by substituting these values there.
N₂×3 = (94×9.8×1.5)+(86×1×9.8)
3N₂ = 2254\sN₂ = 2254/3\sN₂ = 751.33 N
The formula below is used to determine the First Support N1.
N1 + N2 mg + Mg
N1 = (869.8)+(949.8)-751.33 N1 = 1012.67 N1 = mg+Mg-N2
Consequently, each support's upward force is 751.33 N and 1012.67 N, respectively.
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