College

[tex]\frac{1}{2} \times (953 + 62)[/tex] is ______ [tex]953 + 62[/tex].

A. twice as much as
B. half as much as
C. 62 more than
D. 62 less than

Answer :

Let's go through the solution step-by-step:

1. Understand the expression: We have the expression [tex]\(\frac{1}{2} \times (953 + 62)\)[/tex]. This means we're taking half of the sum of 953 and 62.

2. Calculate the original sum:
- Add 953 and 62 together:
[tex]\[
953 + 62 = 1015
\][/tex]

3. Calculate half of the sum:
- Now, take half of 1015:
[tex]\[
\frac{1}{2} \times 1015 = 507.5
\][/tex]

4. Compare half the sum with the original sum:
- We need to determine how the result [tex]\(507.5\)[/tex] relates to the original sum [tex]\(1015\)[/tex].
- Notice that when you take half of the sum (1015), it's naturally less than the full sum.

5. Determine the difference:
- Subtract 507.5 from 1015 to find how much less it is:
[tex]\[
1015 - 507.5 = 507.5
\][/tex]

6. Interpret the relationship:
- Since the result [tex]\(507.5\)[/tex] is exactly half of the original amount [tex]\(1015\)[/tex], it is also 62 less than [tex]\(1015\)[/tex].
- Therefore, we say the expression [tex]\(\frac{1}{2} \times (953 + 62)\)[/tex] is "62 less than" [tex]\(953 + 62\)[/tex].

So, the expression [tex]\(\frac{1}{2} \times (953 + 62)\)[/tex] is 62 less than [tex]\(953 + 62\)[/tex].