High School

[tex]ABCD[/tex] is a rectangle.

[tex]E[/tex] is the point on [tex]AD[/tex] such that [tex]AE:ED = 4:3[/tex].

Work out the area of the rectangle.

Answer :

To find the area of rectangle [tex]\(ABCD\)[/tex], we need to know both the length and the width. However, the given information is not complete as there are no specific dimensions provided for the rectangle. Let's analyze what we have:

1. [tex]\(ABCD\)[/tex] is a rectangle, which means opposite sides are equal and the angles are [tex]\(90^{\circ}\)[/tex].

2. [tex]\(E\)[/tex] is a point on the side [tex]\(AD\)[/tex] such that the ratio [tex]\(AE:ED = 4:3\)[/tex]. This implies that [tex]\(AD\)[/tex] is divided into parts that are in this specific ratio.

The calculation segment included:
- [tex]\(15x \cdot 7 = 255\)[/tex]
- [tex]\(255 \div 2 = 127.5\)[/tex]
- Subtracting calculation: [tex]\(180 - 125.5 = 52.0\)[/tex]

However, these calculations do not provide direct information about the rectangle's dimensions. Given the lack of full data:
- We can't deduce either the length or width of the rectangle directly.
- Thus, we cannot compute the area without additional details.

If these dimensions are provided or if there's a specific method to deduce them using missing information, we can calculate the area. For now, we don't have enough to determine the area of [tex]\(ABCD\)[/tex] with certainty.