High School

Taub is trying to find the height of a radio antenna on the roof of a local building. She stands at a horizontal distance of 20 meters from the building. The angle of elevation from her eyes to the roof (point A) is 43°, and the angle of elevation from her eyes to the top of the antenna (point B) is 47°. If her eyes are 1.57 meters from the ground, find the height of the antenna (the distance from point A to point B). Round your answer to the nearest meter if necessary.

Answer :

Answer:

Approximately [tex]2.8\; \text{m}[/tex].

Step-by-step explanation:

Refer to the diagram attached. Let [tex]{\sf E}[/tex] denote the eyes of the observer, and let [tex]{\sf L}[/tex] denote the point where the building is at the same height as [tex]{\sf E}[/tex]. [tex]m \angle {\sf ELA} = m \angle {\sf ELB} = 90^{\circ}[/tex].

It is given that [tex]{\sf EL} = 20\; \text{m}[/tex], [tex]m\angle {\sf AEL} = 47^{\circ}[/tex], and [tex]m\angle {\sf BEL} = 43^{\circ}[/tex].

In right triangle [tex]\triangle {\sf AEL}[/tex], the angle [tex]m\angle {\sf AEL} = 47^{\circ}[/tex] is opposite to the leg [tex]{\sf AL}[/tex], and adjacent to the leg [tex]{\sf EL} = 20\; \text{m}[/tex]. Hence, the length of the [tex]{\sf AL}[/tex] can be found using [tex]\tan \angle {\sf AEL}[/tex]:

[tex]\displaystyle \tan \angle {\sf AEL} = \frac{(\text{opposite})}{(\text{adjacent})} = \frac{(\textsf{AL})}{(\textsf{EL})}[/tex].

[tex](\textsf{AL}) = (\textsf{EL})\, \tan \angle \textsf{AEL} = (20\; \text{m})\, \tan(47^{\circ})[/tex].

Similarly, in right triangle [tex]\triangle \textsf{BEL}[/tex]:

[tex](\textsf{BL}) = (\textsf{EL})\, \tan \angle \textsf{BEL} = (20\; \text{m})\, \tan(43^{\circ})[/tex].

The height of the antenna, [tex]\textsf{AB}[/tex], would be:

[tex](\textsf{AB}) = (\textsf{AL}) - (\textsf{BL}) = (20\; \text{m})\, \left(\tan(47^{\circ}) - \tan(43^{\circ})\right) \approx 2.8\; \text{m}[/tex].

Note that the height of the eyes does not matter. The reason is that both the height of the rooftop and the height of the antenna are relative to the height of the eyes. When subtracting, the height of the eyes is eliminated from the equation.