High School

Suppose the scores of seven members of a women's golf team are [tex]68, 62, 60, 64, 70, 66,[/tex] and [tex]72[/tex]. Find the mean, median, and midrange.

a. Mean [tex]=64[/tex], median [tex]=64[/tex], midrange [tex]=64[/tex]

b. Mean [tex]=65[/tex], median [tex]=64[/tex], midrange [tex]=66[/tex]

c. Mean [tex]=66[/tex], median [tex]=77[/tex], midrange [tex]=65[/tex]

d. Mean [tex]=66[/tex], median [tex]=66[/tex], midrange [tex]=66[/tex]

Please select the best answer from the choices provided:
A
B
C
D

Answer :

We are given the scores:
$$68,\, 62,\, 60,\, 64,\, 70,\, 66,\, 72.$$

**Step 1. Calculate the Mean**

The mean (average) is found by summing all the scores and then dividing by the number of scores. First, find the sum:
$$68 + 62 + 60 + 64 + 70 + 66 + 72 = 462.$$
There are 7 scores, so the mean is:
$$\text{Mean} = \frac{462}{7} = 66.$$

**Step 2. Find the Median**

To find the median, first arrange the scores in increasing order:
$$60,\, 62,\, 64,\, 66,\, 68,\, 70,\, 72.$$
Since there are 7 scores (an odd number), the median is the middle value, which is the 4th value in the ordered list:
$$\text{Median} = 66.$$

**Step 3. Determine the Midrange**

The midrange is the average of the smallest and largest values. The smallest score is $60$ and the largest is $72$, thus:
$$\text{Midrange} = \frac{60 + 72}{2} = \frac{132}{2} = 66.$$

**Conclusion**

The mean is $66$, the median is $66$, and the midrange is $66$. Therefore, the best answer is:

$$\textbf{D. Mean } = 66, \textbf{ median } = 66, \textbf{ midrange } = 66.$$