High School

Suppose the scores of seven members of a women's golf team are [tex]$68, 62, 60, 64, 70, 66$[/tex], and [tex]$72$[/tex]. Find the mean, median, and midrange.

a. Mean [tex]$=64$[/tex], median [tex]$=64$[/tex], midrange [tex]$=64$[/tex]
b. Mean [tex]$=65$[/tex], median [tex]$=64$[/tex], midrange [tex]$=66$[/tex]
c. Mean [tex]$=66$[/tex], median [tex]$=77$[/tex], midrange [tex]$=65$[/tex]
d. Mean [tex]$=66$[/tex], median [tex]$=66$[/tex], midrange [tex]$=66$[/tex]

Please select the best answer from the choices provided:
A
B
C
D

Answer :

Sure, let's find the mean, median, and midrange of the given scores: 68, 62, 60, 64, 70, 66, and 72.

### Mean
To find the mean, we sum up all the scores and then divide by the number of scores:

1. Add up all the scores:
[tex]\( 68 + 62 + 60 + 64 + 70 + 66 + 72 = 462 \)[/tex]

2. Divide the total by the number of scores:
[tex]\(\frac{462}{7} \approx 66.0\)[/tex]

So, the mean is [tex]\(66.0\)[/tex].

### Median
To find the median, we first need to arrange the scores in ascending order and then find the middle value.

1. Arrange the scores:
60, 62, 64, 66, 68, 70, 72

2. Since there are 7 scores, the middle one (4th score) is the median:
The median score is [tex]\(66\)[/tex].

### Midrange
The midrange is the average of the lowest and highest values.

1. Identify the smallest and largest scores:
- Smallest score: 60
- Largest score: 72

2. Calculate the midrange:
[tex]\(\frac{60 + 72}{2} = 66.0\)[/tex]

So, the midrange is [tex]\(66.0\)[/tex].

Based on these calculations, the best answer is:

- Mean = 66.0
- Median = 66
- Midrange = 66.0

Hence, the correct choice is d.