High School

Suppose the population of a certain bacteria in a laboratory sample is 100. If it doubles in population every 6 hours, what is the growth rate? How many bacteria will be there in two days? Use the formula: [tex]A = P \cdot e^{rt}[/tex]

Answer :

Final answer:

The growth rate of the bacteria population is approximately 0.1155. After two days, there will be an estimated 20,909.63 bacteria in the sample.

Explanation:

To determine the growth rate of the bacteria population, we can use the formula A = P * e^(rt), where A is the final population, P is the initial population, r is the growth rate, and t is the time in hours. In this case, the initial population (P) is 100 and the time (t) is 6 hours. Since the population doubles every 6 hours, the growth rate (r) can be calculated as follows:

r = ln(2) / 6 ≈ 0.1155

To find the population after two days (48 hours), we can plug in the values into the formula:

A = 100 * e^(0.1155 * 48) ≈ 20,909.63

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