High School

Suppose that during the icy hot lab, 60 kJ of energy is transferred to 3700 g of water at 25°C. What would be the final temperature of the water?

Answer :

Final answer:

To calculate the final temperature of the water, we can use the equation Q = m * c * ΔT. Given that 60 kJ of energy is transferred to 3700 g of water at 25°C, the final temperature would be approximately 3.77°C.

Explanation:

To calculate the final temperature of the water, we can use the equation Q = m * c * ΔT, where Q is the heat transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.

Given that 60 kJ of energy is transferred to 3700 g of water, we can solve for the final temperature using the equation:

60 kJ = 3700 g * 4.18 J/g°C * (final temperature - 25°C)

Simplifying the equation, we find:

final temperature - 25°C = 60,000 J / (3700 g * 4.18 J/g°C)

final temperature - 25°C ≈ 3.77°C

Therefore, the final temperature of the water would be approximately 3.77°C.

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